## Related questions with answers

A refrigerator is operated by a $0.25-\mathrm{hp}(1 \mathrm{hp}$= $746\ watts)$ motor. If the interior is to be maintained at $4.50^{\circ} \mathrm{C}$ and the room temperature on a hot day is $38^{\circ} \mathrm{C}$, what is the maximum heat leak (in $watts$) that can be tolerated? Assume that the coefficient of performance is $50 \%$ of the maximum theoretical value. What happens if the leak is greater than your calculated maximum value?

Solution

Verified**GIVEN:**

A $P=0.25 \text{ hp}$ engine powers a refrigerator. The interior temperature is maintained at $T_1=4.5 ^\circ \text{C}$ while the surroundings temperature is $T_2=38 ^\circ \text{C}$. The refrigerator operates at $50\%$ of the maximum theoretical efficiency. Unit of horsepower is related to Watts in the following way: $1 \text{ hp} =746 \text{ W}$.

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