Related questions with answers

Andresen Company had the following quality costs for the years ended June 30, 20X1 and 20X2:

20X120X2 Prevention costs:  Quality audits $30,000$45,000 Vendor certification 60,00090,000 Appraisal costs:  Product acceptance 45,00067,500 Process acceptance 37,50054,750 Internal failure costs:  Retesting 51,00045,000 Rework 108,00090,000 External failure costs: 60,000 Recalls 75,000150,000 Warranty 165,000\begin{array}{lrr} & \mathbf{2 0 X 1} & \mathbf{2 0 X 2} \\ \hline \text { Prevention costs: } & & \\ \text { Quality audits } & \$ 30,000 & \$ 45,000 \\ \text { Vendor certification } & 60,000 & 90,000 \\ \text { Appraisal costs: } & & \\ \text { Product acceptance } & 45,000 & 67,500 \\ \text { Process acceptance } & 37,500 & 54,750 \\ \text { Internal failure costs: } & & \\ \text { Retesting } & 51,000 & 45,000 \\ \text { Rework } & 108,000 & 90,000 \\ \text { External failure costs: } & & 60,000 \\ \text { Recalls } & 75,000 & 150,000 \\ \text { Warranty } & 165,000 & \end{array}

At the end of 20X1, management decided to increase its investment in control costs by 50% for each category’s items, with the expectation that failure costs would decrease by 20% for each item of the failure categories. Sales were $6,000,000 for both 20X1 and 20X2.

  1. Calculate the budgeted costs for 20X2, and prepare an interim quality performance report.

  2. Comment on the significance of the report. How much progress has Andresen made?

Question

A resistor consists of a solid cylinder of radius rr and length LL. The resistor has resistance RR and is carrying current ii. Use the Poynting vector to calculate the power radiated out of the surface of the resistor.

Solution

Verified
Answered 1 year ago
Answered 1 year ago
Step 1
1 of 7

We will start with equation for power radiated from surface with surface area AA that is radiating electromagnetic waves with intensity II. Since intensity of Poynting vector is same as intensity of the electromagnetic waves I=SI=S, we will plug in expression for Poynting vector into the equation for power radiated from surface. Then we will plug in expression for electric field inside the cylindrical conductor and expression for magnetic field of cylindrical conductor. Since electric field of the cylindrical conductor will be expressed in terms of voltage across cylindrical conductor, we will use Ohm's law to write voltage across cylindrical conductor in terms of given current through the cylindrical conductor and resistance of cylindrical conductor.

Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy
Continue with GoogleContinue with Facebook

Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy
Continue with GoogleContinue with Facebook

More related questions

1/4

1/7