Question

A rigid pipe 4 km4 \mathrm{~km} long and 12 cm/12 \mathrm{~cm} / in diameter discharges water (ρ=1000 kg/m3)\left(\rho=1000 \mathrm{~kg} / \mathrm{m}^3\right) at the rate of 0.03 m3/s0.03 \mathrm{~m}^3 / \mathrm{s}. If a valve at the end of the pipe is closed in 3 s3 \mathrm{~s}, what is the maximum force that will be exerted on the valve as a result of the pressure rise? Suppose that the water temperature is 10C10^{\circ} \mathrm{C}.

Solution

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Given:
Fluid Density, ρ=1000 kgm3\rho = 1000 ~ \mathrm{\frac{kg}{m^3}}
Length of Pipe. L=4 kmL = 4 ~ \mathrm{km}
Diameter of Pipe, d=12 cmd = 12 ~ \mathrm{cm}
Volumetric Flow Rate, Q=0.03 m3sQ = 0.03 ~ \mathrm{\frac{m^3}{s}}
Closure Time, t=3 st = 3 ~ \mathrm{s}

Required:
Force on the Valve, FF

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