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Question

A rigid pipe $4 \mathrm{~km}$ long and $12 \mathrm{~cm} /$ in diameter discharges water $\left(\rho=1000 \mathrm{~kg} / \mathrm{m}^3\right)$ at the rate of $0.03 \mathrm{~m}^3 / \mathrm{s}$. If a valve at the end of the pipe is closed in $3 \mathrm{~s}$, what is the maximum force that will be exerted on the valve as a result of the pressure rise? Suppose that the water temperature is $10^{\circ} \mathrm{C}$.

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 9**Given**:

Fluid Density, $\rho = 1000 ~ \mathrm{\frac{kg}{m^3}}$

Length of Pipe. $L = 4 ~ \mathrm{km}$

Diameter of Pipe, $d = 12 ~ \mathrm{cm}$

Volumetric Flow Rate, $Q = 0.03 ~ \mathrm{\frac{m^3}{s}}$

Closure Time, $t = 3 ~ \mathrm{s}$

**Required**:

Force on the Valve, $F$

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