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# A rock is on an inclined surface. The rock is originally at rest, but starts to slide down the incline. The magnitude of the force on the surface due to the rock is $F_{SR}$ , and the magnitude of the force on the rock due to the surface is $F_{RS}$. If we com- pare these forces, we find $(A)$ $F_{SR}. always. $(B)$ $F_{SR}=F_{RS}$ when the rock is at rest but then $F_{SR}>F_{RS}$. $(C)$ $F_{SR}=F_{RS}$ always. $(D)$ $F_{SR}>F_{RS}$ always.

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A rock on an inclined surface starts of at rest at this time the force exerted by the surface is equal to the force exerted by the rock on the surface. When the rock starts sliding down the inclined surface, there is a greater force on the surface due to the rock than the force on the rock due to the surface.

Thus, if we compare the force on the surface due to the rock to the force on the rock due to the surface, we find that the magnitude of the force on the surface due to the rock $F_{SR}$ is equal to the magnitude of the force on the rock due to the surface $F_{RS}$ when the rock is at rest, but then the magnitude of the force on the surface due to the rock $F_{SR}$ is greater than the magnitude of the force on the rock due to the surface $F_{RS}$ when the rock starts sliding down the inclined surface.

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