A roller coaster goes $26 \mathrm{~m}$ along a section of track sloping $10^{\circ}$ below the horizontal, followed by a $15-\mathrm{m}$ section sloping upward at $6^{\circ}$, followed by an 18-m section of level track. Find the net displacement.

Position vector $\vec{r}$ has magnitude of $13.0 \mathrm{~m}$ and direction angle $210^{\circ}$. (a) Find its components.

Find the $x$ - and $y$-components of these vectors in the $x-y$ plane: (c) $\vec{C}$ has magnitude $10 \mathrm{~m}$ and points in the $-y$-direction.

Find the $x$ - and $y$-components of these vectors in the $x-y$ plane: (b) $\vec{B}$ has magnitude $13 \mathrm{~m}$, direction $30^{\circ}$.

Find the $x$ - and $y$-components of these vectors in the $x-y$ plane: (a) $\vec{A}$ has magnitude $6.4 \mathrm{~m}$, direction angle $80^{\circ}$.

The position vectors $\vec{r}_1=2.39 \mathrm{~m} \hat{\imath}-5.07 \mathrm{~m} \hat{\jmath}$ and $\vec{r}_2=-3.56 \mathrm{~m} \hat{\imath}+0.98 \mathrm{~m} \hat{\jmath}$. (c) Show graphically that $\vec{r}_1-\vec{r}_2$ is equivalent to $\vec{r}_1+\left(-\vec{r}_2\right)$