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A series RLR L circuit is often used as a low-pass filter. Consider a resistor RR and inductor LL connected in series to an oscillating source of emf with amplitude Emax \mathcal{E}_{\text {max }}. In terms of Emax \mathcal{E}_{\text {max }}, what is the amplitude of the voltage across the resistor for a low frequency, when ωL/R=1/10\omega L / R=1 / 10 ? For a high frequency, when ωL/R=10\omega L / R=10 ? At what frequency is the amplitude of the voltage across the resistor equal to Emax/2\mathcal{E}_{\max } / \sqrt{2} ?

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In this problem, an RL circuit used as a low-pass filter is connected in series to a source with an amplitude of Emax\mathcal{E}_\text{max}. Our objective is to determine the amplitude of the voltage across the resistor when ωL/R=1/10\omega L/R = 1/10, and when ωL/R=10\omega L/R = 10. Also, we want to determine the frequency where in the amplitude of the voltage across the resistor is E/2\mathcal{E}/\sqrt{2}.

To solve the desired parameters in this problem, we will have to use the formula for the reactance of a capacitor :

XL=ωL(1)X_L = \omega L \tag{1}

Also, we can solve for the amplitude of the voltage across the resistor by applying voltage division:

VR,max=RR2+XL2Emax(2)V_\text{R,max} = \frac{R}{\sqrt{R^2+ {X_L}^2}} \mathcal{E}_\text{max} \tag{2}

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