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Question

A shot-putter accelerates a 7.30-kg shot from rest to 14.0 m/s14.0 \mathrm{~m} / \mathrm{s}. If this motion takes 2.00 s2.00 \mathrm{~s}, what average power was supplied?

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Answered 1 year ago
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Given the following data

m=7.30 kgv=14.0 msΔt=2.00 s\begin{aligned} m&=7.30\ \mathrm{kg}\\ v&=14.0\ \mathrm{\dfrac{m}{s}}\\ \Delta t&=2.00\ \mathrm{s}\\ \end{aligned}

we are to calculate the average power P\overline{P}. To do so, we'll use

P=WΔt\begin{equation} \overline{P}=\dfrac{W}{\Delta t} \end{equation}

and the work-kinetic energy theorem,

W=ΔK\begin{equation} W=\Delta K \end{equation}

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