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A simple generator has a square armature 6.0 cm6.0 \mathrm{~cm} on a side. The armature has 8585 turns of 0.65 cm0.65 \mathrm{~cm} diameter copper wire and rotates in a 0.65 T0.65 \mathrm{~T} magnetic field. The generator is used to power a lightbulb rated at 12.0 V12.0 \mathrm{~V} and 25.0 W25.0 \mathrm{~W}. At what rate should the generator rotate to provide 12.0 V12.0 \mathrm{~V} to the bulb? Consider the resistance of the wire on the armature.

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Givens:\color{#4257b2}\text{Givens:}

We are given a generator of a square armature rotating in a magnetic field to power a light bulb,

  • l=6  cml= 6\;\mathrm{cm}: is the length of the square armature of the generator.

  • N=85  turnsN= 85\;\mathrm{turns}: is the number of loops of the generator coil.

  • dw=0.65  mmd_w= 0.65\;\mathrm{mm}: is the diameter of the copper wire of the generator coil.

  • B=0.65  TB= 0.65\;\mathrm{T}: is the magnetic field in which the generator rotates.

  • V=12  VV= 12\;\mathrm{V}: is the voltage needed to turn on the light bulb.

  • P=25  WP= 25\;\mathrm{W}: is the power rated for the light bulb.

We are required to evaluate the angular frequency ω\omega by which the generator should rotate to turn on the light bulb.

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