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Question

A slender rod, 0.240 m0.240 \mathrm{~m} long, rotates with an angular speed of 8.80rad/s8.80 \mathrm{rad} / \mathrm{s} about an axis through one end and perpendicular to the rod. The plane of rotation of the rod is perpendicular to a uniform magnetic field with a magnitude of 0.650 T0.650 \mathrm{~T}. What is the potential difference between its ends?

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Answered 1 year ago
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b)

The potential difference between the rod's end is simply the magnitude of the emf induced in the rod. That is

v=ε=0.165  V.v = |\varepsilon| = 0.165\;\mathrm{V}.

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