Question

A small sphere is hung by a string from the ceiling of a van. When the van is stationary, the sphere hangs vertically. However, when the van accelerates, the sphere swings backward so that the string makes an angle of

θ\theta

with respect to the vertical. (a) Derive an expression for the magnitude a of the acceleration of the van in terms of the angle

θ\theta

and the magnitude g of the acceleration due to gravity. (b) Find the acceleration of the van when

θ=10.0\theta = 10.0 ^ { \circ }

(c) What is the angle

θ\theta

when the van moves with a constant velocity?

Solutions

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The angle of the sphere when the van is moving is θ\theta. We need to: a) derive the expression of the acceleration, first by the terms of the angle, then by the terms of the gravitational acceleration b) calculate the acceleration of the van if:

θ=10.0o\theta= 10.0^o

c) calculate the angle when the van is moving with a constant velocity.

We know the gravitational acceleration is:

g=9.8m/s2g=9.8\,\text{m/s}^2

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