Question

A solenoid that is 72 cm72 \mathrm{~cm} long produces a magnetic field of 1.8 T1.8 \mathrm{~T} within its core when it carries a current of 8.1 A8.1 \mathrm{~A}. How many turns of wire are contained in this solenoid?

Solution

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Answered 2 years ago
Answered 2 years ago
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We use the equation (22-12)

B=μ0NILB=\dfrac{\mu_0 N I}{L}

We invert this to find NN

We get

N=LBμ0I=(0.72 m)(1.8 T))(4π107 Tm/A)(8.1 A)=127324N=\dfrac{L B}{\mu_0 I}=\dfrac{(0.72\ \mathrm{m})(1.8\ \mathrm{T}))}{(4 \pi \cdot 10^{-7}\ \mathrm{Tm/A})(8.1\ \mathrm{A})}=\boxed{127324}

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