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# A solid S is generated by revolving the region between the x-axis and the curve y=$\sqrt { \sin x } ( 0 \leq x \leq \pi )$about the x-axis. An integral expression for the volume of S is ___.

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In this exercise, we need to find an integral expression for the volume of a solid generated by revolving the region between the $x$ axis and the curve:

$y(x)=\sqrt{\sin x},$

about the $x$-axis, from $x_{1}=0$ to $x_{2}=\pi$ as boundaries, but first, we need to know:

How can we determine an integral expression for a volume of a solid generated by revolving the region between a curve and the $x$ axis?

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