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Question

A solid S is generated by revolving the region between the x-axis and the curve y=

sinx(0xπ)\sqrt { \sin x } ( 0 \leq x \leq \pi )

about the x-axis. An integral expression for the volume of S is ___.

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In this exercise, we need to find an integral expression for the volume of a solid generated by revolving the region between the xx axis and the curve:

y(x)=sinx,y(x)=\sqrt{\sin x},

about the xx-axis, from x1=0x_{1}=0 to x2=πx_{2}=\pi as boundaries, but first, we need to know:

How can we determine an integral expression for a volume of a solid generated by revolving the region between a curve and the xx axis?

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