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A solution of KClO3\mathrm{KClO}_{3} is prepared using 75 grams of the solute in enough water to make 0.250 liters of solution. The gram-formula mass of KClO3\mathrm{KClO}_{3} is 122 grams per mole. Assuming the solution is saturated, determine the temperature of the solution.

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75 g of KClO3_3 are dissolved in 250 g of water. Solubility is expressed asa m(solute)/100 g solvent so:

75gKClO3250gH2O=XgKClO3100gH2O\mathrm{\dfrac{75\:g\:KClO_3}{250\:g\:H_2O}=\dfrac{X_g\:KClO_3\:}{100\:g\:H_2O}}

XgKClO3=30g\mathrm{X_gKClO_3=30g}

From the graph, we can see that 30 g KClO3_3 (100 g H2_2O is saturated at 700^0C.

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