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# A solution of $\mathrm{KClO}_{3}$ is prepared using 75 grams of the solute in enough water to make 0.250 liters of solution. The gram-formula mass of $\mathrm{KClO}_{3}$ is 122 grams per mole. Assuming the solution is saturated, determine the temperature of the solution.

Solution

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75 g of KClO$_3$ are dissolved in 250 g of water. Solubility is expressed asa m(solute)/100 g solvent so:

$\mathrm{\dfrac{75\:g\:KClO_3}{250\:g\:H_2O}=\dfrac{X_g\:KClO_3\:}{100\:g\:H_2O}}$

$\mathrm{X_gKClO_3=30g}$

From the graph, we can see that 30 g KClO$_3$ (100 g H$_2$O is saturated at 70$^0$C.

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