Question

A spaceship moving 0.80c0.80 \: \mathrm{c} direction away from Earth fires a missile that the spaceship measures to be moving at 0.80c0.80 \: \mathrm{c} perpendicular to the ship's direction of travel. Find the velocity components and speed of the missile as measured by Earth.

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K system is system attached to Earth and K' is attached to spaceship. Let the v=0.8cv=0.8 \: c be relative speed beetween the system and let's say that it is in x direction. In K' only speed that is measured is in y direction, uy=0.8cu_{\text{y}}'=0.8 \: c. Then velocity components measured from system K (from Earth) are:

x direction:ux=ux+v1+vc2uxux=0+0.8c1+0ux=0.8c,y direction:uy=uyγ(1+vc2ux)uy=0.8c11(0.8)2(1+0)uy=0.48c,z direction:uz=uzγ(1+vc2ux)uz=011(0.8)2(1+0)uz=0,\begin{align*} & \text{x direction:} \\ u_{\text{x}} &= \frac{u_{\text{x}}' + v }{ 1 + \frac{v}{c^2}u_{\text{x}}'} \\ u_{\text{x}} &= \frac{0 + 0.8 \: c}{1 + 0} \\ u_{\text{x}} &= \boxed{0.8 \: c}, \\ & \text{y direction:} \\ u_{\text{y}} &= \frac{u_{\text{y}}'}{\gamma \left( 1+ \frac{v}{c^2} u_{\text{x}}' \right)} \\ u_{\text{y}} &= \frac{0.8 \: c}{ \frac{1}{\sqrt{1 - (0.8)^2}} \left( 1 + 0 \right)} \\ u_{\text{y}} &= \boxed{0.48 \: c}, \\ & \text{z direction:} \\ u_{\text{z}} &= \frac{u_{\text{z}}'}{\gamma \left( 1+ \frac{v}{c^2} u_{\text{x}}' \right)} \\ u_{\text{z}} &= \frac{0 }{ \frac{1}{\sqrt{1 - (0.8)^2}} \left( 1 + 0 \right)} \\ u_{\text{z}} &= \boxed{0}, \\ \end{align*}

and speed of projectile is:

u=ux2+uy2u=(0.8c)2+(0.48c)2u=0.93c<c.\begin{align*} u &= \sqrt{u_{\text{x}}^2 + u_{\text{y}}^2} \\ u &= \sqrt{(0.8 \: c)^2 + (0.48 \:c)^2} \\ u &= \boxed{0.93 \:c \: < \: c}. \end{align*}

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