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A squirrel has xx- and yy-coordinates (1.1 m,3.4 m)(1.1 \mathrm{~m}, 3.4 \mathrm{~m}) at time t1=0t_1=0 and coordinates (5.3 m,0.5 m)(5.3 \mathrm{~m},-0.5 \mathrm{~m}) at time t2=3.0 st_2=3.0 \mathrm{~s}. For this time interval, find
(b) the magnitude and direction of the average velocity.

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(b)

We know that the magnitude of the average velocity is given by applying the Pythagorean theorem to the average velocity components. Hence,

vavg=vx,avg2+vy,avg2\| v_{avg}\|=\sqrt{v_{x,avg}^2+v_{y,avg}^2}

Plug from the final red results in part (a) above.

vavg=1.42+(1.3)2\| v_{avg}\|=\sqrt{1.4^2+(-1.3)^2}

vavg=1.91  m/s\boxed{\| v_{avg}\|={\color{#c34632}\bf 1.91}\;\rm m/s}

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