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Question

A step-up transformer increases 25 V to 120 V. What is the current in the secondary coil as compared to the primary coil?

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$\dfrac {V_{s}}{V_{p}} = \dfrac{N_{s}}{N_{p}}$ and $\ \dfrac{N_{s}}{N_{p}} = \dfrac {I_{s}}{I_{p}} \ \ $ so  VsVp=IsIp\ \dfrac {V_{s}}{V_{p}} = \dfrac {I_{s}}{I_{p}}

Use equations 21-6 and 21-7 from the book to relate the current and voltage ratios.

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