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Question

A student says the equation of a line perpendicular to

y=1213x+4713y=\frac{12}{13} x+\frac{47}{13}

is

y=1312x+4713y=\frac{13}{12} x+\frac{47}{13}

. Explain the student's error.

Solution

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The student's error in the given equation that is perpendicular to the first equation is that the slope is just a reciprocal. In determining the equation perpendicular to the given equation of a line, the slope to be used should be negative reciprocal. It should be 1312-\dfrac{13}{12}.

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