## Related questions with answers

Question

A student stretches a spring, attaches a 1.00-kg mass to it, and releases the mass from rest on a frictionless surface. The resulting oscillation has a period of 0.500 s and an amplitude of 25.0 cm. Determine the spring constant.

Solution

VerifiedStep 1

1 of 2Since $\omega=2\pi f=\sqrt{k/m}$, we can find the spring constant easily:

$\begin{gather*} k=(2\pi f)^2m=4\pi^2f^2m=4\pi^2\cdot (2\mathrm{~Hz})^2\cdot 1\mathrm{~kg}\approx \boxed{158\mathrm{~N/m}} \end{gather*}$

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