Try the fastest way to create flashcards
Question

A student stretches a spring, attaches a 1.00-kg mass to it, and releases the mass from rest on a frictionless surface. The resulting oscillation has a period of 0.500 s and an amplitude of 25.0 cm. Determine the spring constant.

Solution

Verified
Step 1
1 of 2

Since ω=2πf=k/m\omega=2\pi f=\sqrt{k/m}, we can find the spring constant easily:

k=(2πf)2m=4π2f2m=4π2(2 Hz)21 kg158 N/m\begin{gather*} k=(2\pi f)^2m=4\pi^2f^2m=4\pi^2\cdot (2\mathrm{~Hz})^2\cdot 1\mathrm{~kg}\approx \boxed{158\mathrm{~N/m}} \end{gather*}

Create a free account to view solutions

Create a free account to view solutions

Recommended textbook solutions

Physics for Scientists and Engineers: A Strategic Approach with Modern Physics 4th Edition by Randall D. Knight

Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

4th EditionISBN: 9780133942651 (8 more)Randall D. Knight
3,508 solutions
Mathematical Methods in the Physical Sciences 3rd Edition by Mary L. Boas

Mathematical Methods in the Physical Sciences

3rd EditionISBN: 9780471198260 (1 more)Mary L. Boas
3,355 solutions
Fundamentals of Physics 10th Edition by David Halliday, Jearl Walker, Robert Resnick

Fundamentals of Physics

10th EditionISBN: 9781118230718 (3 more)David Halliday, Jearl Walker, Robert Resnick
8,971 solutions
College Physics 11th Edition by Chris Vuille, Raymond A. Serway

College Physics

11th EditionISBN: 9781305952300Chris Vuille, Raymond A. Serway
5,021 solutions

More related questions

1/4

1/7