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A study of driving costs based on 2012 medium-sized sedans found that the average cost (car payments, gas, insurance, upkeep, and depreciation) in cents per mile is approximately C(x)=1910.5x1.72+42.9 (5x20)C(x)=\frac{1910.5}{x^{1.72}}+42.9 \ (5 \leq x \leq 20) where x (in thousands) denotes the number of miles the car is driven each year. Show that C is a decreasing function of x on the interval (5, 20). What does your result tell you about the average cost of driving a 2012 mediumsized sedan in terms of the number of miles driven?

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It is given that the average cost in cents per mile is approximately

C(x)=1910.5x1.72+42.9      (5x20)C(x) = \frac{1910.5}{x^{1.72}} + 42.9\ \ \ \ \ \ (5 \leq x \leq 20)

where xx (in thousands) denotes the number of miles the car is driven in each year.

The function CC can be rewritten as

C(x)=1910.5x1.72+42.9      (5x20)C(x) = 1910.5x^{-1.72} + 42.9\ \ \ \ \ \ (5 \leq x \leq 20)

The derivative of C(x)C(x) then, is

C(x)=1910.5(1.72)x2.72=3286.06x2.72=3286.06x2.72\begin{align*} C'(x) & = 1910.5(-1.72)x^{-2.72}\\ & = -3286.06x^{-2.72}\\ & = -\frac{3286.06}{x^{2.72}} \end{align*}

Since 5x205 \leq x \leq 20, we obtain C(x)<0C'(x) < 0 for all xx and therefore, we can say that CC is a decreasing function of xx in the interval (5,20)(5,20).

It means that the average cost of driving a 2012 medium-sized sedan decreases as the number of miles driven increases. This is shown in the figure below.

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