## Related questions with answers

A system consists of three particles with these masses and velocities: mass 3.0 kg, moving north at 3.0 m/s; mass 4.0 kg, moving sooth at 5.0 m/s; and mass 7.0 kg, moving north at 2.0 m/s. What is the total momentum of the system?

Solutions

VerifiedIn this problem, we have to find the total momentum of the system using the given information.

$\begin{align*} m_1&=3\ \text{kg}\\ m_2&=4\ \text{kg}\\ m_3&=7\ \text{kg}\\ v_1&=3\ \frac{\text m}{\text s}\\ v_2&=5\ \frac{\text m}{\text s}\\ v_3&=2\ \frac{\text m}{\text s}\\ \end{align*}$

$\textbf{Given: }$

The mass of the first particle is $m_{1} = 3 \mathrm{~kg}$. The velocity of the first particle is $v_{1} = 3 \mathrm{~m/s}$ in the north. The mass of the second particle is $m_{2} = 4 \mathrm{~kg}$. The velocity of the second particle is $v_{2} =5 \mathrm{~m/s}$ in the south. The mass of the third particle is $m_{3} = 7 \mathrm{~kg}$. The velocity of the third particle is $v_{3} = 2 \mathrm{~m/s}$ in the north.

$\textbf{Required: }$

Finding the total momentum.

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