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Question

A system undergoes a process consisting of the following two steps: Step 1: The system absorbs 72 J of heat while 35 J of work is done on it. Step 2: The system absorbs 35 J of heat while performing 72 J of work. Calculate ΔE for the overall process.

Solution

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Answered 2 years ago
Answered 2 years ago
Step 1
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We first calculate the energy change (ΔE\Delta E) of the system on the first step. Heat (qq) was absorbed\textit{absorbed}, so the system gains energy $\text{\underline{(positive qq)}}.Work(. Work (w$) was done to the system\textit{done to the system}, so it gains energy again $\text{\underline{(positive ww)}}$:

ΔE1=q+w=72 J+35 J=107 J\begin{align*} \Delta E_1 &= q + w\\ &= \mathrm{72~J + 35~J}\\ &= \mathrm{107~J} \end{align*}

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