Question

A thin tubular shaft of circular cross section with inside diameter 100 mm is subjected to a torque of 5000 Nm5000\ \mathrm{N} \cdot \mathrm{m}. If the allowable shear stress is 42 MPa, determine the required wall thickness t by using (a) the approximate theory for a thin-walled tube, and (b) the exact torsion theory for a circular bar.

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a) To determine the required thickness of the wall using the approximate theory, we will use the expression for maximum shear stress in the circular cross section 3-83:

τmax=T2πr2t \begin{aligned} &\tau_{max}=\frac{T}{2\pi r^2 t} \end{aligned}

Where we will set the shear stress in the shaft to its maximum allowable value of τmax=42\tau_{max}=42 MPa, T=5000T=5000 N\cdotm=5000×103=5000\times 10^3 N\cdotmm is the torque acting on the shaft, tt is the thickness of the tube. rr is the median radius of the shaft. We can express the median radius as:

r=1002+t2r=50+t2 \begin{aligned} &r=\frac{100}{2}+\frac{t}{2}\\\\ &r=50+\frac{t}{2} \end{aligned}

Substituting the set expressions:

42=5000×1032π(50+t2)2t \begin{aligned} &42=\frac{5000\times 10^3}{2\pi \Big(50+\dfrac{t}{2}\Big)^2 t} \end{aligned}

Solving numerically for tt gives us solution t=6.662t=6.662 mm.

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