## Related questions with answers

Question

A tiger leaps horizontally from a 6.5-m-high rock with a speed of 3.5 m/s. How far from the base of the rock will she land?

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 5$x=x_0 + v_xt$

$y=y_0 + v_yt-\dfrac{1}{2}gt^2$

These are the two projectile motion equations. We'll set the base of the cliff to be at the origin so $x_0 = 0$ and $y_0 = 6.5$. Also, the initial speed is $v_x=3.5$ and $v_y=0$

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