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Question

A transformation T: Vn+VnV_n + V_n is described as, T rotates every point through the same angle ϕ\phi about the origin. That is, T maps a point with polar coordinates (r, 0) onto the point with polar coordinates (r,θ+ϕ)(r, \theta+\phi), where ϕ\phi is fixed. Also, Tmaps 0 onto itself. Determine whether T is linear. If T is linear, describe its null space and range, and compute its nullity and rank.

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Let (r,θ)(r,\theta) be a point in V2V_2, in polar coordinates. Then, its Cartesian coordinates are (x,y)(x,y), where

x=rcosθ,y=rsinθ.\begin{align*}x&=r\cos\theta,\\ y&=r\sin\theta.\end{align*}

The function TT is defined such that, in polar coordinates, T(r,θ)=(r,θ+ϕ)T(r,\theta)=(r,\theta+\phi), where ϕ\phi is constant. In Cartesian coordinates, this means that T(x,y)=(x0,y0)T(x,y)=(x_0,y_0), where

x0=rcos(θ+ϕ)=r(cosθcosϕsinθsinϕ)=cosϕrcosθsinϕrsinθ=cosϕxsinϕy,y0=rsin(θ+ϕ)=r(sinθcosϕ+cosθsinϕ)=cosϕrsinθ+sinϕrcosθ=sinϕx+cosϕy.\begin{align*}x_0&=r\cos(\theta+\phi)\\ &=r(\cos\theta\cos\phi-\sin\theta\sin\phi)\\ &=\cos\phi\cdot r\cos\theta-\sin\phi\cdot r\sin\theta\\ &=\cos\phi\cdot x-\sin\phi\cdot y,\\ y_0&=r\sin(\theta+\phi)\\ &=r(\sin\theta\cos\phi+\cos\theta\sin\phi)\\ &=\cos\phi\cdot r\sin\theta+\sin\phi\cdot r\cos\theta\\ &=\sin\phi\cdot x+\cos\phi\cdot y.\end{align*}

Therefore, in Cartesian coordinates, T(x,y)=(cosϕxsinϕy,sinϕx+cosϕy)T(x,y)=(\cos\phi\cdot x-\sin\phi\cdot y,\sin\phi\cdot x+\cos\phi\cdot y). We know that any function T:V2V2T:V_2\to V_2 of the form T(x,y)=(ax+by,cx+dy)T(x,y)=(ax+by,cx+dy) must be linear, so TT is linear.

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