Question

A tungsten (Z = 74) target is bombarded by electrons in an x-ray tube. The K, L, and M energy levels for tungsten have the energies 69.5, 11.3, and 2.30 keV, respectively. (a) What is the minimum value of the accelerating potential that will permit the production of the characteristic

KαK_{\alpha}

and

KβK_{\beta}

lines of tungsten? (b) For this same accelerating potential, what is

λmin{\lambda}_{min}

? What are the (c)

KαK_{\alpha}

and (d)

KβK_{\beta}

wavelengths?

Solution

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(a)\textbf{(a)} To produce a characteristic KαK_\alpha and KβK_\beta lines of tungsten, an electron must be removed from the KK-shell the energy required to remove an electron form this shell is just the energy of this shell. The KK energy level for tungsten have an energy of 69.5 keV, thus the minimum potential difference that can be used to remove an electron from KK level is:

V=69.5 kV\boxed{V=69.5 \mathrm{~kV}}

(b)\textbf{(b)} The minimum wavelength is given by:

λmin=hcE\lambda_\text{min}=\dfrac{hc}{E}

where EE is the energy of the KK level, so:

λmin=(6.626×1034 Js)(2.998×108 m/s)69.5×103×1.602×1019 J=1.78×1011 m=17.8 pm\begin{align*}\lambda_\text{min}&=\dfrac{(6.626 \times 10^{-34} \mathrm{~J\cdot s})(2.998 \times 10^8 \mathrm{~m/s})}{69.5 \times 10^3 \times 1.602 \times 10^{-19} \mathrm{~J}} \\ &=1.78 \times 10^{-11} \mathrm{~m}\\ &=17.8 \mathrm{~pm} \end{align*}

λmin=17.8 pm\boxed{\lambda_\text{min}=17.8 \mathrm{~pm}}

(c)\textbf{(c)} According to figure 40-15, the energy of a photon associated with the KαK_\alpha line is given by:

EKα=EKEL=69.5 keV11.3 keV=58.2 keV\begin{align*} E_{K_\alpha}&=E_K-E_L\\ &=69.5 \mathrm{~keV}-11.3\mathrm{~keV}\\ &=58.2\mathrm{~keV} \end{align*}

and the wavelength that corresponds this energy is:

λ=(6.626×1034 Js)(2.998×108 m/s)58.2×103×1.602×1019 J=2.13×1011 m=21.3 pm\begin{align*}\lambda&=\dfrac{(6.626 \times 10^{-34} \mathrm{~J\cdot s})(2.998 \times 10^8 \mathrm{~m/s})}{58.2 \times 10^3 \times 1.602 \times 10^{-19} \mathrm{~J}} \\ &=2.13\times 10^{-11} \mathrm{~m}\\ &=21.3\mathrm{~pm} \end{align*}

λ=21.3 pm\boxed{\lambda=21.3\mathrm{~pm}}

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