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A. Two identical conducting spheres are placed with their centers 0.30 m apart. One is given a charge of +12×109C+12 \times 10^{-9} \mathrm{C}. The other is given a charge of 18×109C-18 \times 10^{-9} \mathrm{C}. Find the electric force between them. Given: Unknown:

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Answered 2 years ago
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The following are the given in the problem:

q1=+12×109 Cq2=18×109 Cr=0.3 mkc=8.99×109Nm2C2\begin{align*} q_{1} &= +12 \times 10^{-9} \text{ C} \\ q_{2} &= -18 \times 10^{-9} \text{ C} \\ r &= 0.3 \text{ m} \\ k_{c} &= 8.99 \times 10^{9} \dfrac{\text N \cdot \text m^{2}}{\text C^{2}} \end{align*}

The problem wants us to determine the electric force between two identical conducting spheres. This can be solved by applying Coulumbs' law as stated below:

Fe=k(q1q2r2)\begin{align} F_{e} &= k_{} \cdot \left(\dfrac{q_{1} \cdot q_{2}}{r^{2}}\right) \end{align}

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