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Question

A uniform flux density of 1 T is perpendicular to the plane of a five-turn circular coil of radius 10 cm. Find the flux linking the coil and the flux linkages. Suppose that the field is decreased to zero at a uniform rate in 1 ms. Find the magnitude of the voltage induced in the coil.

Solution

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From problem description we have:

B=1 Wbm2, r=10 cm=0.1 m, N=5 turns, Δt=1 msB = 1 \ \frac{\text{Wb}}{\text{m}^2}, \ r =10 \ \text{cm} = 0.1 \ \text{m}, \ \text{N} = 5 \ \text{turns}, \ \Delta t = 1 \ \text{ms}

Notice that flux density BB is perpendicular to the surface AA surrounded by the coil. The magnetic flux passing through surface AA is:

ϕ=BA=Br2π=1 Wbm20.12 m2π=0.0314 Wb\phi = B \cdot A = B \cdot r^2 \pi = 1 \ \frac{\text{Wb}}{\text{m}^2} \cdot 0.1^2 \ \text{m}^2 \cdot \pi = \boxed{0.0314 \ \text{Wb}}

The flux linkages we can determ as follows:

λ=Nϕ=5 turns0.0314 Wb=0,157 Wbturns\lambda = \text{N} \cdot \phi = 5 \ \text{turns} \cdot 0.0314 \ \text{Wb} = \boxed{0,157 \ \text{Wb} \cdot \text{turns}}

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