Question

A voltaic cell utilizes the following reaction:

Al(s)+3Ag+(aq)Al3+(aq)+3Ag(s)\mathrm { Al } ( s ) + 3 \mathrm { Ag } ^ { + } ( a q ) \longrightarrow \mathrm { Al } ^ { 3 + } ( a q ) + 3 \mathrm { Ag } ( s )

What is the effect on the cell emf of each of the following changes? A solution of

AgNO3AgNO_3

is added to the cathode half-cell, increasing the quantity of

Ag+Ag^+

but not changing its concentration.

Solution

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Answered 2 years ago
Answered 2 years ago
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Given reaction :-

Al(s) + 3Ag+^+(aq) \rightarrow Al3+^{3+}(aq) + 3Ag(s)

Expression of E can be written as :-

E = E^{\circ} - 0.0592Vn\dfrac{0.0592 V}{n}logProductReactant\dfrac{\text{Product}}{\text{Reactant}}

E = E^{\circ} - 0.0592Vn\dfrac{0.0592 V}{n}log[Al3+][Ag+]3\dfrac{[Al^{3+}]}{[Ag^+]^3}

Increasing the quantity of Ag+^+ ion does not effect the Q of cell and hence does not effect the emf of the cell.

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