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Question
(a) What is the force per meter on a lightning bolt at the equator that carries 20,000 A perpendicular to Earth’s field? (b) What is the direction of the force if the current is straight up and Earth’s field direction is due north, parallel to the ground?
Solution
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1 of 3a) The magnitude of the force on a wire of length carrying a current and making an angle with a magnetic field of density is given by:
$\vert \vec{F} \vert = B \, I \, l \, \sin{(\theta)}$
Rearranging to get the force per unit length:
$\dfrac{\vert \vec{F} \vert}{l} = B \, I \, \sin{(\theta)}$
Therefore,
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