Question

a. Which

KeqK _ { \mathrm { eq } }

corresponds to a negative value of

ΔG,Keq=1000 or Keq=.001?\Delta G ^ { \circ } , K _ { \mathrm { eq } } = 1 0 0 0 \text { or } K _ { \mathrm { eq } } = . 0 0 1 ?

b. Which

KeqK _ { \mathrm { eq } }

corresponds to a lower value of

ΔG,Keq=102 or Keq=105?\Delta G ^ { \circ } , K _ { \mathrm { eq } } = 1 0 ^ { - 2 } \text { or } K _ { \mathrm { eq } } = 1 0 ^ { - 5 } ?

Solution

Verified
Answered 7 months ago
Answered 7 months ago
Step 1
1 of 4

In order to solve this task, we have to follow this equation:

ΔG0=2.303RTlogKeq\textcolor{#4257b2}{\Delta G^0 = -2.303 RT \log K_{eq}}

If we observe the equation shown above, we can see that an interesting part of the equation is going to be logKeq_{eq}.

If Keq_{eq} value is bigger than 1 (Keq_{eq} > 1), logarithm is going to have positive value so ΔG0\textcolor{#4257b2}{\Delta G^0} is going to be negative.

And vice versa, if the Keq_{eq} value is smaller than 1 (Keq_{eq} < 1), logarithm is going to have negative value so ΔG0\textcolor{#4257b2}{\Delta G^0} is going to be positive.

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