Try the fastest way to create flashcards
Question

A wire 4.00 m long and 6.00 mm in diameter has a resistance of 15.0 mΩ\Omega. A potential difference of 23.0 V is applied between the ends. Calculate the resistivity of the wire material.

Solution

Verified
Answered 1 year ago
Answered 1 year ago
Step 1
1 of 2

(c) The resistance for the given wire is:

R=ρLAR=\dfrac{\rho L}{A}

rewrite for ρ\rho, to get:

ρ=RAL\rho=\dfrac{RA}{L}

substitute with the given values to get:

ρ=πRd24L=π(15×103)(6×103)24(4)=1.06×106 Ωm\begin{aligned} \rho&=\dfrac{\pi Rd^2}{4L}\\ &=\dfrac{\pi (15 \times 10^{-3})(6 \times 10^{-3})^2}{4(4)}\\ &=1.06 \times 10^{-6} \mathrm{~\Omega \cdot m} \end{aligned}

ρ=1.06×107 Ωm\boxed{\rho=1.06 \times 10^{-7} \mathrm{~\Omega \cdot m}}

Create a free account to view solutions

Create a free account to view solutions

Recommended textbook solutions

Fundamentals of Physics 8th Edition by Halliday, Resnick, Walker

Fundamentals of Physics

8th EditionISBN: 9780471758013 (2 more)Halliday, Resnick, Walker
9,479 solutions
Fundamentals of Physics 10th Edition by David Halliday, Jearl Walker, Robert Resnick

Fundamentals of Physics

10th EditionISBN: 9781118230718 (3 more)David Halliday, Jearl Walker, Robert Resnick
8,971 solutions
Fundamentals of Physics, Extended 11th Edition by David Halliday, Jearl Walker, Robert Resnick

Fundamentals of Physics, Extended

11th EditionISBN: 9781119306856 (2 more)David Halliday, Jearl Walker, Robert Resnick
9,586 solutions
Halliday and Resnick's Principles of Physics, Global Edition 11th Edition by David Halliday, Jearl Walker, Robert Resnick

Halliday and Resnick's Principles of Physics, Global Edition

11th EditionISBN: 9781119454014David Halliday, Jearl Walker, Robert Resnick
5,354 solutions

More related questions

1/4

1/7