## Related questions with answers

Question

A wire 4.00 m long and 6.00 mm in diameter has a resistance of 15.0 m$\Omega$. A potential difference of 23.0 V is applied between the ends. Calculate the resistivity of the wire material.

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 2**(c)** The resistance for the given wire is:

$R=\dfrac{\rho L}{A}$

rewrite for $\rho$, to get:

$\rho=\dfrac{RA}{L}$

substitute with the given values to get:

$\begin{aligned} \rho&=\dfrac{\pi Rd^2}{4L}\\ &=\dfrac{\pi (15 \times 10^{-3})(6 \times 10^{-3})^2}{4(4)}\\ &=1.06 \times 10^{-6} \mathrm{~\Omega \cdot m} \end{aligned}$

$\boxed{\rho=1.06 \times 10^{-7} \mathrm{~\Omega \cdot m}}$

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