## Related questions with answers

According to a report on traumatic brain injury, the force that a professional boxer’s fist exerts on his opponent’s head is equivalent to being hit with a $5.9 \mathrm{kg}$ bowling ball traveling at $8.9 \mathrm{m} / \mathrm{s}$ that stops in $0.018 s$.Determine the average force that the fist exerts on the head.

Solutions

Verified$\textbf{Givens:}$

$\color{#4257b2}\bullet \bullet$ $m_{ball}=5.9$ kg

$\color{#4257b2}\bullet \bullet$ $v_f=0$ m/s

$\color{#4257b2}\bullet \bullet$ $v_i=8.9$ m/s

$\color{#4257b2}\bullet \bullet$ $\Delta t=0.018$ s

Mass of the ball, m = 5.9 kg

speed of the ball, v = 8.9 m/s

Momentum of the ball = $mv = 5.9 \times 8.9 = 52.51 kg.m/s$ $\\$ time taken to stop, t = 0.018s$

$Average force required to stop =$$\dfrac{change \ in \ momentum}{time \ taken}$ =$\dfrac{52.51-0}{0.018}$ = 2917.22 N$

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