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Question

Air at 20C20^\circ C with a convection heat transfer coefficient of 20W/m2K20 W/m^2 \cdot K blows over a pond. The surface temperature of the pond is at 40C.40^\circ C. Determine the heat flux between the surface of the pond and the air.

Solution

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The heat flux from the pond to the air is

q˙=h(TpondTair)=20(4020)=400 W/m2\dot{q}=h\left(T_\text{pond}-T_\text{air} \right)=20*(40-20)=\color{#c34632}{400\ \text{W/m}^2}

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