Question

Air enclosed in a sphere has density ρ=1.4kg/m3\rho = 1.4 \mathrm { kg } / \mathrm { m } ^ { 3 }. What will the density be if the radius of the sphere is halved, compressing the air within?

Solution

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Let mm be the mass of the enclosed air and V=43πr3V=\dfrac{4}{3}\pi r^3 be the volume of the sphere. Then,

ρ=mV\rho=\dfrac{m}{V}

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