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Question

Algebra Triangle A B C has side lengths of $A B=x^2-x+5, B C=5 x-4$, and $A C=3 x^2-2 x-1$. If $\triangle A B C$ is isosceles where $A B=B C$, find the lengths of all sides.

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 5$AB=BC\\\\x^{2}-x+5=5x-4\\\\x^{2}-6x+9=0\\\\(x-3)^{2}=0\\\\x=3$

Since AB = BC, set up an equation with and solve for x.

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