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Question

All members of the junior class at a local high school took the PSAT exam. The distribution of the results of the mathematics section was found to be approximately normal, with a mean score of 52 and a standard deviation of 6.8. Stephan claimed that he scored better than 90% of the students in the junior class. Use z-sore and your z-table to determine what score Stephan must have earned to be correct.

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Answered 2 years ago
Answered 2 years ago
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The closest value to 9090 percent is 0.89970.8997 and it's achieved for zz-score =1.28=1.28. Now, we can find what score Stephan must have earned.

x=z-score  standard deviation + mean=1.286.8+52=60.704\begin{align*} x&=z\text{-score }\cdot\text{ standard deviation }+\text{ mean}\\ &=1.28\cdot 6.8+52\\ &=60.704 \end{align*}

Because the achieved score must be an integer, Stephan must've achieved a score greater than or equal to 6161.

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