An 80.0-kg skydiver jumps out of a balloon at an altitude of 1 000 m and opens his parachute at an altitude of 200 m. (a) Assuming the total retarding force on the skydiver is constant at 50.0 N with the parachute closed and constant at 3 600 N with the parachute open, find the speed of the skydiver when he lands on the ground. (b) Do you think the skydiver will be injured? Explain. (c) At what height should the parachute be opened so that the final speed of the skydiver when he hits the ground is 5.00 m/s? (d) How realistic is the assumption that the total retarding force is constant? Explain.


Answered 1 year ago
Answered 1 year ago
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m=80  kgm=\textcolor{#c34632}{80\;\mathrm{kg}}

yi=1000  my_i=\textcolor{#c34632}{1000\;\mathrm{m}}

yf=0  my_f=\textcolor{#c34632}{0\;\mathrm{m}}

vi=0  m/sv_i=\textcolor{#c34632}{0\;\mathrm{m/s}}

f1=50  Nf_1=\textcolor{#c34632}{50\;\mathrm{N}}

d1=800  md_1=\textcolor{#c34632}{800\;\mathrm{m}}

f2=3600  Nf_2=\textcolor{#c34632}{3600\;\mathrm{N}}

d2=200  md_2=\textcolor{#c34632}{200\;\mathrm{m}}

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