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An adiabatic air compressor compresses 10 L/s10 \mathrm{~L} / \mathrm{s} of air at 120kPa120 \mathrm{kPa} and 20C20^{\circ} \mathrm{C} to 1000kPa1000 \mathrm{kPa} and 300C300^{\circ} \mathrm{C}. Find (a)(a) the work needed by the compressor, in kJ/kg\mathrm{kJ} / \mathrm{kg}, and (b) the power needed to drive the air compressor, in kWk W.

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Answered 2 years ago
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We have the following data:

Inlet

P1P_1 = 120 kPa

T1T_1 = 20°20 \text{\textdegree}C + 273 = 293 K

V˙1\dot{V}_1 = 10 Ls\dfrac{L}{s} (1 m31000 L)(\dfrac{1 \ m^{3}}{1000 \ L}) = 0.01 m3m^{3}

Outlet

P1P_1 = 1000 kPa

T1T_1 = 300 °\text{\textdegree}C + 273 = 573 K

These are the assumptions in compressors for this problem:

Negligible heat transfer, Q˙\dot{Q} = 0 (well insulated)

Negligible changes in potential energy, Δ\Deltape = 0

Negligible changes in kinetic energy, Δ\Deltake = 0

a) Work required, W\textbf{a) Work required, W}: The work required can be calculated by applying the energy balance equation by net energy to the system. The energy balanced equation for a steady- flow process compressor including the assumptions can be expressed as

Ein=EoutE_{in} = E_{out}

Win+h1=h2W_{in} + h_1 = h_2

Win=h2h1W_{in} = h_2 - h_1

Since enthalpy, h=cpT\textcolor{#4257b2}{h = c_pT} then

Win=Cp(T2T1)W_{in} = C_p(T_2 - T_1)

Where

CpC_p = heat capacity of air @ average of T1T_1 and T2T_2

TavgT_{avg} = T1+T22\dfrac{T_1 + T_2}{2} = 293+5732\dfrac{293 + 573}{2} = 433 K

As per TABLE A-2, Ideal-gas specific heats of various common gases

@400 K, specific heat CpC_p = 1.013 \ kJkgK\dfrac{kJ}{kg \cdot K}

@450 K, specific heat CpC_p = 1.020 \ kJkgK\dfrac{kJ}{kg \cdot K}

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