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Question

An air conditioner with a power input of 1.2 kW is working as a refrigerator (β=3)(\beta=3) or as a heat pump (β=4)\left(\beta^{\prime}=4\right). It maintains an office at 20C^{\circ} \mathrm{C} year round that exchanges 0.5 kW per degree temperature difference with the atmosphere. Find the maximum and minimum outside temperatures for which this unit is sufficient.

Solution

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We are given following data for air conditioner:

W˙=1.2 kW\dot W=1.2\text { kW}

TH=20CT_H=20 C

q˙=0.5 kW C\dot q=0.5\frac{\text{ kW}}{\text{ C}}

βref=3\beta_{ref}=3

βpump=4\beta_{pump}=4

Heat pump COP is given by:

βpump=Q˙HW˙=q˙(THTa)W˙\beta_{pump}=\dfrac{\dot Q_H}{\dot W}=\dfrac{\dot q\cdot (T_H-T_a)}{\dot W}

We can solve it for ambient temperature and get minimum:

Tmin=Ta=THβpumpW˙q˙=2041.20.5=10.4 C\begin{align*} T_{min}&=T_a=T_H-\dfrac{\beta_{pump}\cdot \dot W}{\dot q}\\\\ &=20-\dfrac{4\cdot 1.2}{0.5}\\\\ &=\boxed{10.4\text{ C}} \end{align*}

Refrigerator COP is given by:

βref=Q˙HW˙=q˙(TaTH)W˙\beta_{ref}=-\dfrac{\dot Q_H}{\dot W}=\dfrac{\dot q\cdot (T_a-T_H)}{\dot W}

We can solve it for ambient temperature and get maximum:

Tmax=Ta=TH+βrefW˙q˙=20+31.20.5=27.2 C\begin{align*} T_{max}&=T_a=T_H+\dfrac{\beta_{ref}\cdot \dot W}{\dot q}\\\\ &=20+\dfrac{3\cdot 1.2}{0.5}\\\\ &=\boxed{27.2\text{ C}} \end{align*}

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