Question

An aluminum ion,

Al3+\text{Al}^{3+}

, is only one-third the size of an aluminum atom. How would you explain this?

Solution

Verified
Answered 1 year ago
Answered 1 year ago

For this task, we are asked of the reason why Al3+\text{Al}^{3+} is smaller in comparison to its chargeless Al\text{Al} counterpart.

In general, cations (ions with positive charges) are generally smaller than their chargeless counterparts. This is because removing the outermost electrons of an element (for example, the 33 valence electrons of aluminum in the 33rd energy level) means that the atom has one less occupied energy level resulting in a smaller atomic radius.

This is the reason why aluminum ions are smaller than chargeless aluminum atoms.

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