## Related questions with answers

Question

An aluminum sphere is heated from 11°C to 580°C. If the volume of the sphere is 1.78 cm3 at 11°C, what is the increase in volume of the sphere at 580°C?

Solutions

VerifiedSolution A

Solution B

Answered 1 year ago

Step 1

1 of 3**Given information:**

Initial temperature of an aluminum sphere: $T_1=11\ \mathrm{^oC}$

Final temperature of an aluminum sphere: $T_2=580\ \mathrm{^oC}$

Initial volume of the sphere: $V_1=1.78\ \mathrm{m^3}$

We need to find the increase in volume $\Delta V$ due to increase in temperature.

Answered 2 years ago

Step 1

1 of 2We should use $\Delta V = \beta V_{1} \Delta T$ equation ;

So ;

$\Delta V = ((75 \times 10^{-6}) \text{\textdegree} C^{-1})(1.78 cm^{3})(580 \text{\textdegree} C - 11 \text{\textdegree} C)$

$\Delta V = 7.6 \times 10^{-2} cm^{3}$

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