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Question

An aqueous solution containing 35.9 g of an unknown molecular (no nelectrolyte) compound in 150.0 g of water has a freezing point of - 1.3C^{\circ} \mathrm{C}. Calculate the molar mass of the unknown compound.

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Answered 2 years ago
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The freezing-point depression (4Tf\mathcal 4 T_f) is defined as the freezing point of the pure solvent (TfT_f) minus the freezing point of the solution (TfoT^o_f):

4Tf=TfoTf\mathcal 4 T_f = T_f^o -T_f

4Tf=Kfm\mathcal 4 T_f = K_fm

1.3oC=1.86 oCm×xmolal\mathrm{1.3 ^oC }= \mathrm{ 1.86\text{ } \dfrac{^oC}{m} \times } x_{molal}

xmolal=0.6989 molkgx_{molal}= \mathrm{0.6989 \text{ } \dfrac{mol}{kg} }

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