Question

An Earth satellite used in the global positioning system moves in a circular orbit with period 11 h58 min11 \mathrm{~h} 58 \mathrm{~min}. (a) Determine the radius of its orbit. (b) Determine its speed. (c) The satellite contains an oscillator producing the principal nonmilitary GPS signal. Its frequency is 1575.42MHz1575.42 \mathrm{MHz} in the reference frame of the satellite. When it is received on the Earth's surface, what is the fractional change in this frequency due to time dilation, as described by special relativity? (d) The gravitational blue shift of the frequency according to general relativity is a separate effect. The magnitude of that fractional change is given by

Δff=ΔUgmc2\frac{\Delta f}{f}=\frac{\Delta U_g}{m c^2}

where ΔUg\Delta U_{\mathrm{g}} is the change in gravitational potential energy of an object-Earth system when the object of mass mm is moved between the two points at which the signal is observed. Calculate this fractional change in frequency. (e) What is the overall fractional change in frequency? Superposed on both of these relativistic effects is a Doppler shift that is generally much larger. It can be a red shift or a blue shift, depending on the motion of a particular satellite relative to a GPS receiver

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Given\textbf{Given}

The period TT of the satellite's orbit is

T=11 h 58 min\begin{align*} T=11\ \text{h}\ 58\ \text{min} \end{align*}

The mass of the Earth MM is

M=61024 kg\begin{align*} M=6\cdot 10^{24}\ \text{kg} \end{align*}

The radius of the Earth RR is

R=6.4106 m\begin{align*} R=6.4\cdot 10^6\ \text{m} \end{align*}

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