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An electric field is applied to a solution containing bromide ions. As a result, the ions move through the solution with an average drift speed of 3.7×107 m/s.3.7 \times 10^{-7}\ \mathrm{m} / \mathrm{s}. The mobility of bromide ions in solution is 8.1×108 (m/s)/(N/C).8.1 \times 10^{-8}\ (\mathrm{m} / \mathrm{s}) /(\mathrm{N} / \mathrm{C}) . What is the magnitude of the net electric field inside the solution?

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Knowns:\textbf{\underline{Knowns:}}

It is given that the drift speed of the bromide ions in the solution is v=3.7×107v= 3.7 \times 10^{-7} (m/s) and the mobility of the bromide ions in solution is 8.1×1088.1\times 10^{-8}(m/s)/(N/C).

And the applied electric field on the solution can be calculated from the following equation

E=vμ(1)\tag{1} E =\dfrac{v}{\mu}

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