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Question

An electric field is applied to a solution containing bromide ions. As a result, the ions move through the solution with an average drift speed of $3.7 \times 10^{-7}\ \mathrm{m} / \mathrm{s}.$ The mobility of bromide ions in solution is $8.1 \times 10^{-8}\ (\mathrm{m} / \mathrm{s}) /(\mathrm{N} / \mathrm{C}) .$ What is the magnitude of the net electric field inside the solution?

Solution

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1 of 3$\textbf{\underline{Knowns:}}$

It is given that the drift speed of the bromide ions in the solution is $v= 3.7 \times 10^{-7}$ (m/s) and the mobility of the bromide ions in solution is $8.1\times 10^{-8}$(m/s)/(N/C).

And the applied electric field on the solution can be calculated from the following equation

$\tag{1} E =\dfrac{v}{\mu}$

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