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Question

An electric water heater having a 200-L capacity heats water from $23 \text { to } 55^{\circ} \mathrm{C}.$ Heat transfer from the outside of the water heater is negligible, and the states of the electrical heating element and the tank holding the water do not change significantly. Perform a full exergy accounting, in kJ, of the electricity supplied to the water heater. Model the water as incompressible with a specific heat $c=4.18 \mathrm{kJ} / \mathrm{kg} \cdot \mathrm{K}.$ Let $T_{0}=23^{\circ} \mathrm{C}.$

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 13Data:

- $V=200\mathrm{\,l}$ -Tank volume.
- $t_1=23\mathrm{\,C}$ -Inital temperature.
- $t_2=55\mathrm{\,C}$ -Final temperature.
- $c=4.18\mathrm{\,\dfrac{kJ}{kg\cdot K}}$ -Sepcific heat.
- $T_0=296\mathrm{\,K}$ -Dead state temperature.

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