Question

An electron beam in an oscilloscope is deflected by the electric field produced by oppositely charged metal plates. If the electric field between the plates is 2.00×105N/C2.00 \times 10 ^ { 5 } \mathrm { N } / \mathrm { C } directed downward, what is the force on each electron when it passes between the plates?

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1 Concepts and Principles

If an arbitrary charge q\textcolor{black}{q} is placed in an electric field of magnitude E\textcolor{black}{E}, it experiences an electric force\textbf{electric force} of magnitude:

Fe=qE\begin{equation*} F_e=|q|E\tag{*} \end{equation*}

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