Question

An exceptional standing jump would raise a person 0.80 m0.80 \mathrm{~m} off the ground. To do this, what force must a 68kg68-\mathrm{kg} person exert against the ground? Assume the person crouches a distance of 0.20 m0.20 \mathrm{~m} prior to jumping, and thus the upward force has this distance to act over before he leaves the ground.

Solution

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Answered 1 year ago
Answered 1 year ago
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Let's write the known quantities as follows:

  • m=68  kgm = 68\;\mathrm{kg}
  • h2=0.80  mh_2 = 0.80\;\mathrm{m}
  • h1=0.20  mh_1 = 0.20\;\mathrm{m}

Our goal is to calculate the force that needs to be exerted on the person in order to perform the described jump.

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