Question

An expectant father paces back and forth, producing the position-versus-time graph shown in Figure 2-25 . Without performing a calculation, indicate whether the father's velocity is positive, negative, or zero on each of the following segments of the graph: B.

Solution

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To calculate the magnitude of the velocity we have to calculate the graph of the line at point B. To calculate the slope we have the endpoints of the line as (1,2) and (2,2) from the graph shown. Now we get the average velocity

V avg= Total distance Total time= slope=2221=0 m/s\begin{align*} V_{\text{ avg}}&=\dfrac{\text{ Total distance}}{\text{ Total time}}=\text{ slope}\\ &=\dfrac{2-2}{2-1}\tag{\textcolor{#4257b2}{the slope between points $(x_1,y_1)$ and $(x_2,y_2)$ would be $\dfrac{y_2-y_1}{x_2-x_1}$}}\\ &=0 \text{ m/s} \end{align*}

Hence, the velocity at point B will be 0 m/s.

Now the answer from the part (b) says that velocity should be zero and the calculated we have is zero. So, it is cross-verified.

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