Question

An eyeglass prescription calls for a lens with an optical power of +2.9+2.9 diopters. What is the focal length of this lens?

Solution

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The refractive power is

R=2.9 dioptersR = 2.9 \ \mathrm{diopters}

The focal length is,

f=1R=12.9 diopters=0.3448 m=34.48 cm\begin{align*} f &= \dfrac{1}{R} \\ &= \dfrac{1}{2.9 \ \mathrm{diopters}} \\ &= 0.3448 \ \mathrm{m} \\ &= \boxed{34.48 \ \mathrm{cm}} \end{align*}

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