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Question

# An ice cube tray holds $325 \mathrm{~g}$ of water. If the water initially has a temperature of $25^{\circ} \mathrm{C}$, how many kilojoules of heat must be removed to cool and freeze the water at $0^{\circ} \mathrm{C} ?(10.5)$

Solution

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In this task, we need to calculate the total heat in kilojoules $\mathrm{(kJ)}$ that is removed by the process of cooling and freezing water.

Given :

$\mathrm{m_{H_2O}=325\ g}$

$\mathrm{T_{initial}=25\degree C}$

$\mathrm{T_{final}=0\degree C}$

$\mathrm{SH_{(H_2O)}=4.184\ \frac{J}{g\times \degree C}}$

$\mathrm{Heat\ of\ fusion_{(H_2O)}=334\ J/g}$

Need :

$\mathrm{Total\ heat= ?}$

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