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An ice cube tray holds 325 g325 \mathrm{~g} of water. If the water initially has a temperature of 25C25^{\circ} \mathrm{C}, how many kilojoules of heat must be removed to cool and freeze the water at 0C?(10.5)0^{\circ} \mathrm{C} ?(10.5)

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Answered 1 year ago
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In this task, we need to calculate the total heat in kilojoules (kJ)\mathrm{(kJ)} that is removed by the process of cooling and freezing water.

Given :

mH2O=325 g\mathrm{m_{H_2O}=325\ g}

Tinitial=25°C\mathrm{T_{initial}=25\degree C}

Tfinal=0°C\mathrm{T_{final}=0\degree C}

SH(H2O)=4.184 Jg×°C\mathrm{SH_{(H_2O)}=4.184\ \frac{J}{g\times \degree C}}

Heat of fusion(H2O)=334 J/g\mathrm{Heat\ of\ fusion_{(H_2O)}=334\ J/g}

Need :

Total heat=?\mathrm{Total\ heat= ?}

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